# Basics of Probability for Data Science explained with examples

## Introduction

Statistically, the probability of any one of us being here is so small that you’d think the mere fact of existing would keep us all in a contented dazzlement of surprise– Lewis Thomas

For anyone taking first steps in data
science, Probability is a must know concept. Concepts of probability
theory are the backbone of many important concepts in data science like
inferential statistics to Bayesian networks. It would not be wrong to
say that the journey of mastering statistics begins with probability.

In this guide, I will start with basics
of probability. Then I’ll introduce binomial distribution, central limit
theorem, normal distribution and Z-score. If they sound scary right now
– just hold on for a few minutes. I have explained each concept with an
example.

I have explained each concept in a
simplistic manner to avoid overload of mathematical concepts. At the end
of the guide, I have given you two fun and exciting challenges. Go
though them and post your answer in the comments sections. Let’s see how
many of you can answer them correctly.

Let’s explore probability together!

## Table of Contents

- What is Probability?
- Random Variables
- Calculating Probability
- Binomial Distribution
- Continuous Random variable
- Central Limit Theorem
- Area under a Normal Distribution
- Z scores
- Open Challenges

## 1. What is Probability?

Simply put, probability is an intuitive
concept. We use it on a daily basis without necessarily realising that
we are speaking and applying probability to work.

Life is full of uncertainties. We don’t
know the outcomes of a particular situation until it happens. Will it
rain today? Will I pass the next math test? Will my favorite team win
the toss? Will I get a promotion in next 6 months? All these questions
are examples of uncertain situations we live in. Let us map them to few
common terminology which we will use going forward.

**Experiment**– are the uncertain situations, which could have multiple outcomes. Whether it rains on a daily basis is an experiment.**Outcome**is the result of a single trial. So, if it rains today, the outcome of today’s trial from the experiment is “It rained”**Event**is one or more outcome from an experiment. “It rained” is one of the possible event for this experiment.**Probability**is a measure of how likely an event is. So, if it is 60% chance that it will rain tomorrow, the probability of Outcome “it rained” for tomorrow is 0.6

### Why do we need probability?

In an uncertain world, it can be of
immense help to know and understand chances of various events. You can
plan things accordingly. If it’s likely to rain, I would carry my
umbrella. If I am likely to have diabetes on the basis of my food
habits, I would get myself tested. If my customer is unlikely to pay me a
renewal premium without a reminder, I would remind him about it.

So knowing the likelihood might be very beneficial.

## 2. Random Variables

To calculate the likelihood of occurence
of an event, we need to put a framework to express the outcome in
numbers. We can do this by mapping the outcome of an experiment to
numbers.

Let’s define X to be the outcome of a coin toss.
X = outcome of a coin toss

Possible Outcomes:

- 1 if heads
- 0 if tails

Let’s take another one.

Suppose, I win the game if I get a sum
of 8 while rolling two fair dice. I can define my random variable Y to
be (the sum of the upward face of two fair dice )

Y can take values = (2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)A few things to note about random variables:

- Each value of the random variable may or may not be equally likely. There is only 1 combination of dice, with sum 2{(1,1)}, while a sum of 5 can be achieved by {(1,4), (2,3), (3,2), (4,1)}. So, 5 is more likely to occur as compared to 2. On the contrary, the likelihood of a head or a tail in a coin toss is equal and 50-50.
- Sometimes, the random variables can only take fixed values, or values only in a certain interval. For example in a dice, the top face will only show values between 1 and 6. It cannot take a 2.25 or a 1.5. Similarly, when a coin is flipped, it can only show heads and tails and nothing else. On the other hand, if I define my random variable to be the amount of sugar in orange. It can take any value like 1.4g, 1.45g, 1.456g, 1.4568g as so on. All these values are possible and all infinite values between them are also possible. So, in this case, the random variable is continuous with a possibility of all real numbers.
- Don’t think random variable as a traditional variable (even though both are called variables) like y=x+2, where the value of y is dependent on x. Random variable is defined in terms of the outcome of a process. We quantify the process using the random variable.

## 3. Calculating Probability by principle of counting

Let’s say you went to a fair. There is a
stall playing the game of spinning wheel. There are two colors evenly
spread on the wheel – red and green. If you land on red, you lose, if
you land on green you win.

So what happens when you spin the wheel?
You either win or you lose? There is no third outcome in this case. If
the wheel is fair, there is a 50% chance of winning and 50% chance of
losing.

Next, suppose the organizer decides to increase the prize money and reduce the green area. Now only ¼

^{th}area is green and ¾^{th }is red.
How likely are you to win now?

Only 25%! This 25% or .25 is the probability of winning.

### Two throws of a dice

The next stall is our favorite dice
stall, where we win if we get a sum of 8 in two throws. Let’s see if we
have more chances to win here.

Let’s take random variable X to be the
sum of two throws. X can take values (2, 3, 4, 5, 6, 7, 8, 9, 10, 11,
12). Let’s see the probability of each number.

Let’s see the probability of each number.

There are 6 possibilities in the first
throw (we can get any number) and same 6 in the second. So total number
if combinations would be 36.

Let’s see how:

2{(1,1)} => 1/36

3{(1,2),(2,1)} => 2/36

4{(2,2),(3,1),(1,3)} => 3/36

5{(1,4),(4,1),(2,3),(3,2)} => 4/36

6{(3,3),(1,5),(5,1),(2,4),(4,2)} => 5/36

7{(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)} => 6/36

8{(2,6),(6,2),(3,5),(5,3),(4,4)} => 5/36

9{(3,6),(6,3),(5,4),(4,5)} => 4/36

10{(4,6),(6,4),(5,5)} => 3/36

11{(5,6),(6,5)} => 2/36

12{(6,6)} = > 1/36

So, the chance of success here is 5/36
or approximately 1 in 7, while failure is 31/36. So, unless the stall
rewards me 7x of the money I bet on winning, it is a bad game to
participate in.

We can write this as:

- p (Success)= 5/36
- p (Failure)= 31/36

You can also see that the total probability is 1. There are only these 2 possibilities.

Let’s see how these probabilities look like. The probability function for a discrete random variable is the

**probability mass function.**It shows the exact probabilities for a particular value of the random variable.
Here is an important thing to note, a
sum of 2.5 is not possible on the throw of two dice. So essentially, my
random variable is discrete. There are only fixed integer values that it
can take and we can see the probabilities of each occurring.

## 4. Binomial Distribution

Most of the times, the situations we
encounter are pass-fail type. The democrats either win or lose the
election. I either get a heads or tails on the coin toss. You either win
or lose your football game (assuming that there is always a forced
outcome). So there are only two outcomes – win and lose or success and
failure. The likelihood of the two may or may not be the same.

Let us understand this through an interesting example.

Let’s say your football team is playing a
series of 5 games against your opponent. Who ever wins more games (out
of 5) wins the title.

Let us say, your team might is more skilled and has 75% chances of winning. So, there is a 25% chance of losing it.

**What is the probability of you winning the series?**Is it 75% or is it something else?

Let us find out. What are the possible scenarios in playing 5 games?

WWWWW, WWWWL, WWWLL, WWLLL, WLLLL, LLLLL, LWWWW and so on….
So for the first game, there are two
possibilities, you either win or lose, again for the second game we have
two possibilities. Assuming that the first game has no effect on the
outcome of the second – No one gets tired, no one gets under pressure
after losing etc.

So let’s define our random variable X to
be a number of wins in 5 games. Remember probability of winning is 0.75
and losing is 0.25. Assume that a tie doesn’t happen.

**X=Number of wins in 5 games**

So the first game has 2 outcomes – win and lose, second again has 2 and so on.

So total possibilities is 2*2*2*2*2 = 32

- P (X=0) denotes the probability that you lose all the games and
there is only one way that can happen i.e. {LLLLL} =
0.25*0.25*0.25*0.25*0.25 (multiplying the probabilities of losing the
each time, lost first time
**and**second time**and**third time and so on..) - P(X=1) denotes the probability that you win only 1 game i.e.(WLLLL or LWLLL or LLWLL or LLLWL or LLLLW). So there are 5 cases where you win 1 game = 5*0.75*0.25*0.25*0.25*0.25=0.0146

^{5}C

_{2 }()

so, the Probability for getting

**k**successes in

**n**Bernoulli trails is given by:

**P(X=k) =**[here p is the probability of success and q is the probability of failure]

^{n}C_{k }p^{k }q^{n-k},
Let’s see how this comes.

- P(X=2) denotes the probability that you win 2 games. So there are
^{5}C_{2}() = 10 cases where you win 2 games. Hence probability = 10*0.75*0.75*0.25*0.25*0.25=0.088 - P(X=3) denotes the probability that you win 3 games. So, there are
^{5}C_{3}() =10 cases where you win 3 games. Hence probability = 10*0.75*0.75*0.75*0.25*0.25=0.264 - Similarly, P(X=4) = 0.395
- P(X=5) = 0.237

What we just calculated were discrete
probabilities for a Binomial distribution. If we look at these
probabilities we get something like:

As you can see the probability of winning the series is much higher than 0.75.

The general definition of a

**binomial distribution is the discrete probability distribution of the number of success in a sequence of n independent Bernoulli trials**(having only yes/no or true/false outcomes).
If the events are equally likely to
occur i.e. p = q = 0.5, the probability distribution looks something
like the graph below. Here the probability of success and failure is the
same.

What difference do we see in the two
probability distributions? The first one is skewed towards right.
Reason being the likelihood to win is more, hence more wins are more
likely than more losses.

In the second case when wins and losses are equally likely, so the distribution is symmetrical.

**Let’s assume that probability of winning and losing is equal. p=q=0.5**

Now, What if I increase my number of
trials? What if I play 20 games of football with a probability of
winning and losing to be 50-50? There are a lot more possibilities and
combinations. The bars get thinner and thinner.

The bars get thinner and thinner.

What if I play an infinite number of times with equal probability for winning and losing?

The bars get infinitely small and the
probability distribution looks something like a continuous set of bars
which are very close, almost continuous. This now becomes a

**probability density function**. Notice that this now becomes a continuous function.Let’s point out some interesting things that happened.

- The probabilities are high for the mean values of the random variables. When we were playing 5 football games, the random variable (X = the wins) could take values between 0 – 5. The mean value being 2.5. The probability is highest for 2 and 3. When we move towards the continuous curve, the probability is highest for the exact mean
- The probabilities are low as we move away from the mean.

## 5. Continuous random variables

Let’s see some cases where the random
variables are continuous. Let’s say the weatherman is trying to measure
the amount of rainfall that will happen tomorrow.

Let’s say the rainfall likely to happen
is around 2 cm. But will it be exactly 2 cm? It can be 2.001 or 2.000001
or 2.000000001 and an infinite number of values in between. It’s even
impossible for us to measure if it’s exactly 2 cm.

So, we calculate the probability of it,
being in a range. We calculate the probability of rainfall being in the
range of 2 cm to 2.01 cm. It will be the sum of probabilities for all
values between 2 and 2.01. The area under the probability density
function with limits 2 and 2.01 will give us that.

The probability density function may or may not be symmetrical.

### Life of an insect

Suppose there is an insect whose
lifespan ranges from 0 to 16 days. We’re looking for the probability
that it will die in around 5 to 6 days. Again we would need the sum of
probabilities for all values between 5 days and 6 days.

We look at the probability density
function and find the area of the graph under the limits of 5 and 6. We
can use definite integration under the desired limits for the
probability density to find the area. We’re often interested in the
probability of a range of values rather than the probability of an exact
value.

We can now imagine that the probability
at a particular point would be the area of the thinnest possible bar we
can imagine. To calculate the probability at x, we would need the area
from x to x+Δ, where Δ is very very small.

The total probability density function would then be the collection of all such areas / probabilities.The formula of the probability density function can be written as:

For a point x, Δ is the small value
right after the point x. We try to calculate the probability from x to
x+ Δ, with limit if Δ tends to 0.

## 6. The Central Limit Theorem

So when you have huge amount of data,
you can be confused how to make sense of it. It is difficult to know
what’s happening underneath it. To tackle this problem, what we do is
take a small chunk of data & look at it. But we won’t be satisfied
with just a single chunk. We’d try to look at multiple chunks to be sure
of results.

Let’s say we have the cholesterol levels
of all the people in India, we can look at the mean, median and mode of
the data. Maybe plot a histogram with sensible ranges and look at the
data. Let’s assume this is how the data looks like. The mean of this
data is 153.2

But this huge amount of data is really
tough to process. To process it, we take the data of some 50 people and
calculate their mean.

We again take a sample of some 50 people
and calculate the mean and we keep doing that for quite a number of
times. We now plot the means of these samples.

We see that these sample means form a
frequency distribution which looks very symmetrical. The frequency
around the mean of the actual data is the highest and gradually reduces
as we move away from the mean on the either side.

So when we take means of cholesterol
levels of 50 people, again and again, we observe the mean values are
around 150-160. Only a few mean values is more than 170 and less than
140. There are very, very few over 190 or less than 110.

We can easily convert the frequencies to
see probabilities. If we divide the frequency of a bin (range like 110
to 120) by the total number of data points, we get the probabilities of
each bin. So, now the frequency distribution becomes a probability
distribution of the same shape. The probability distribution approaches
more and more towards

The probability distribution approaches
more and more towards symmetry, when the sample size that we use to
create those means, is very large. As the sample size approaches
infinity, the probability distribution becomes a perfectly symmetrical
where the center of the curve is the mean of the population. The curve
is known as normal distribution.

### What is a normal distribution?

The normal distribution informally called as a bell curve looks like this:The equation of the normal distribution happens to be:

Here µ is the mean of the data while σ is the standard deviation of the data.

The normal distribution is perfectly
symmetrical about the mean. The probabilities move similarly in both
directions around the mean. The total area under the curve is 1, since
summing up all the possible probabilities would give 1.

The distribution might vary a bit
depending upon how spread the data is. If the data has a very high range
and standard deviation, the normally distributed curve would be spread
out and flatter, since a large number of values would be sufficiently
away from the mean.

Also, if a lot of values are away from
the mean, the probability for data being around the mean also drops.
Similarly, if the standard deviation is low, which means most of the
values are near around the mean, there is high probability of the sample
mean being around the mean and the distribution is a lot skinnier. The
higher the standard deviation, the thicker and flatter the curve.

Let’s summarise the main points we saw:

- Area under a probability density function gives the probability for the random variable to be in that range.
- If I have a population data and I take random samples of equal size from the data, the sample means are approximately normally distributed
- There is large probability for the means to be around the actual mean of the data, than to be farther away
- Normal distributions for higher standard deviations are flatter as compared to those for lower standard deviations

## 7. Area Under the Normal Distribution

Now, let’s say I have a dataset of
cholesterol levels of a number of patients and we need to calculate the
probability of how many patients are healthy.

The mean value (µ) for cholesterol of
all the patients is equal to 150 and standard deviation (σ) is equal to
15. The probability density function is a normal distribution given by
the above equation.

**We need to calculate the probability of cholesterol levels to be between 135 (150-15) and 165 (150+15) – the healthy cholesterol range.**

Can you see that the healthy patients
that we are talking about are one standard deviation on either side of
the mean? This means we need to calculate the area under the curve with
135 and 165 as limits. Don’t worry, this area for normal distribution is
already calculated for us and is ~68%.

So always for a normally distributed
data, around 68% of the data falls within 1 standard deviation of the
mean. So probability of the data being within 1 standard deviation if
the mean = 0.68

Let’s also calculate the probability of
being 2 standard deviations away from the mean. Let’s say we need to
warn the patients who are two standard deviations away.

This means 150+30 and 150-30.

The range of area to be calculated now is 120 to 180.

To your surprise, 95% of the values fall in this range.

So the major chunk of the data falls
within 2 standard deviations of the mean. So, we can safely say, that
for the data to be more than 2 standard deviations away from the mean is
highly unlikely – only 5% likely.

So, 95% of the patients have their
cholesterol levels between 120 and 180. And the remaining 5% are really
critical and different from the average values.

## 8. Z Scores

We will encounter a lot of cases, where
we would need to know the probability for the data to be less than or
more than a particular value. This value will not be equal to 1σ or 2σ
away from the mean.

The distance in terms of number of standard deviations, the observed value is away from the mean, is the

**standard**score or the**Z**score.
A positive Z score indicates that the
observed value is Z standard deviations above the mean. Negative Z score
indicates that the value is below the mean.

Observed value = µ+**z**σ [µ is the mean and σ is the standard deviation]

In our cholesterol example, let’s
see where 172 falls on the distribution. We will calculate the Z score
to find the percentage of people having cholesterol less than 172.

172 = 150+Z*15
Here, we see that 172 is 1.47 {(142-150)/15} standard deviations more than the mean. This 1.47 is known as the z value.

Now, we would need to use these limits
to calculate the area under the curve. Remember that the area under the
curve is 1. Let’s calculate the probability of people having a
cholesterol level of less than 172.

To your happiness, you will never have to actually calculate the area under the normal curve, we have the z table
that can be used to calculate the probabilities for particular z
values. The rows of the Z table have the Z score in tens, while the
hundredths decimal is given by the columns. The value is the area under
the curve less than that Z score.

For a particular z score, we can look
into the table to find the probability for values to fall less than that
particular z value. It can be –ve or +ve. If we look out for 1.47, we
find that ~93% data falls less than that. Therefore, 93% patients have
cholesterol less than 172. Also, we can safely say that 7% have
cholesterol more than 172.

## 9. Challenges

Hope you found the guide simple and useful. I hope some one would have given this early in my career. Here are a few challenges for you to try:**Challenge 1:**Contrary to the popular expectation, try calculating the probability of getting 50 heads and 50 tails on 100 flips of fair coins? This expectation is known as the gambler’s fallacy! An approximate answer would suffice!

**Challenge 2:**Try another one – In the United States, the average IQ is 100, with a standard deviation of 15. What percentage of the population would you expect to have an IQ more than 120?

Post your answers in the comments section.

*Via analyticsvidhya*

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